For the reaction 2 H2S(g) + 3O2(g) ---> 2H2O(g) + 2SO2(g), the initial rate of consumption...
For the reaction 2 H2S(g) + 3O2(g) ---> 2H2O(g) + 2SO2(g), the initial rate of consumption for O2 is 0.0471 M/s for the first 46 seconds. What is the concentration of H2O after 46.0 seconds?
Homework Answers
As per the balanced reaction, 3 moles of O2 consumed will lead to 2 moles of H2O formtion.
Concentration of H2O after 46.0 seconds = 2.167 * 2/3 = 1.444 M
Hence the concentration of H2O after 46.0 seconds will be 1.444 M
Note - Post any doubts/queries in comments section.
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