A halfback is initially running south at a speed of 11.2 m/s, quickly cuts to his right, and 0.545 s later is running 60.0° west of south at 11.2 m/s. Find his average acceleration.
Magnitude:
direction ________ north of west.
Here,
let east is the positive x direction and north is the positive y direction
for the initial velocity
u = -11.2 j m/s
final velocity
v = 11.2 * (- sin(60) i - j * cos(60))
Now, for the average acceleration
a = (v - u)/time
a = ( 11.2 * (- sin(60) i - j * cos(60))- (-11.2j))/0.545
a = -17.8 i + 10.3 j
magnitude of acceleration = sqrt(17.8^2 + 10.3^2) = 20.6 m/s^2
the magnitude of acceleration is 20.6 m/s^2
direction = atan(10.3/17.8) degree north of west
the direction = 30.1 degree north of west
the direction of acceleration is 30.1 degree north of west
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