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According to the Behavioral Risk Factor Surveillance, 58% of all Americans have a sedentary lifestyle. Suppose...

According to the Behavioral Risk Factor Surveillance, 58% of all Americans have a sedentary lifestyle. Suppose you select a sample of twelve individuals and find that ten of them do not exercise regularly.

a) Assuming that the Surveillance System is correct, what is the probability that you would have obtained such sample?  

b) Is it likely to observe such a sample if in fact 58% of all Americans have a sedentary lifestyle? YES or NO

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Answer #1

a) probability that you would have obtained such sample :

P(X=10)= (12C10)0.5810(1−0.58)(12-10)    = 0.0502

b)

Yes, since the probability of above event is more than 0.05 , this is not unusual that 10 of 12 do not exercise regularly.

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