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6. The following data are compiled during water of hydration experiment of BaCl2.xH2O. Mass of beaker...

6. The following data are compiled during water of hydration experiment of BaCl2.xH2O.

Mass of beaker + watch glass 35.82 grams
Mass of beaker + watch glass + sample 37.80 grams
Mass of beaker + watch glass + residue after first heating 37.52 grams

Mass of beaker + watch glass + residue after second heating 37.51 grams

What is the formula of the hydrate?

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Answer #1

(Mass of beaker + watch glass + sample 37.80 grams) - (Mass of beaker + watch glass 35.82 grams) = Mass of sample

= 1.98 grams

Mass of beaker + watch glass + residue after first heating 37.52 grams

Mass of water escaped = 37.8 - 37.52 = 0.28 grams

Number of moles of water escaped = 0.28/18 =0.0155

Mass of BaCl2 left = 1.98-0.28 = 1.7 grams

Moles of BaCl2 = 1.7g / 208.23 g/mol = 0.00861

Number of moles of H2O / Moles of BaCl2 = 0.0155 / 0.0861 = 1.8

Which is approximately equals to 2

Formula of the hydrate = BaCl2. 2H2O

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