Question

Data Mass of Beaker 1 13.3949 _ T\५. ५०४१ 130.7 249 13 R.0269 Mass of Beaker 1 + CaCl2 Mass of Beaker 2 Mass of Beaker 2 + KIO S8.3409 Mass of Watch Glass + Filter Paper S9.SIS9 Mass of Watch Glass + Filter Paper + Ca(IO3)2(after 1st Heating) 51. S219 Mass of Watch Glass + Filter Paper + Ca(IO3)2(after 2nd Heating) 131.6489 Mass of Beaker 2 +Residue (after 1st Heating) 131-6349 Mass of Beaker 2 + Residue (after 2nd Heating) your calculation sheet) in Calculations (Show items below steps 1. Mass of CaCl2 used 1. 35 २ Mass of KIO used 2. 1.1259 Mass of Ca(IO3)2 produced 3. Molar Mass of CaCl2 4. Molar Mass of KIO3 5. aiss 24.6 9 Molar Mass of Ca(IO3)2 6. Molar Mass of KCl 7. 0.00913 mokes Moles of CaCl2 used 8. O.00639 mal-es Moles of KIO used 9. .00302 moleo Moles of Ca(IOs): produced 10.

Answer 1

1) These results show the relation of the quantity of products that are formed from the reaction, with the quantity of limit reagent used, for the reaction:

CaCl2 + 2 KIO3 = Ca (IO3) 2 + 2 KCl

2) These results confirm the law of conservation of mass, with a small acceptable deviation of 5%, which can be attributed to human errors.

3) A certain amount of limit reagent that does not react and excess reagent is present in the residue.

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