1. given the joint p.d.f f (x,y)= 2, 0 <x <y <1.
2. show that fx (x)=2(1- x), 0 <x <1 and fy (y)=2y, 0 <y <1
3. show that p(3/4<y<7/8 I x=1/4)=1/6
0〈z,0〈y Given the following joint distributionfrY(x,y)-, cez+2y else Calculate the following 1. The value of c that makesfxy a proper pdf 2. The marginal distribution function fx(z) 3. The marginal distribution function fy () 4. P(X 1) 7. The random variables X and Y are independent if it is possible to write fxy (x, y) as the product of Íx (x) and fy (y) such that/xy(z, y) = k . Íx (x) . fy(y) for some value of k. Are...
The joint p.d.f of \(X\) and \(Y\) is given by$$ f(x, y)=\left\{\begin{array}{ll} c(1-y), & 0 \leq x \leq y \leq 1 \\ 0 & \text { otherwise. } \end{array}\right. $$Determine the value of \(c\). Find the marginal density of \(X\) and the marginal density of \(Y\) Find the conditional density of \(X\) given \(Y\). Are \(X\) and \(Y\) independent? Why? Find \(E(X-2 Y)\).
Let (X,Y) have joint pdf given by f(rw)-y <x, 0 < x < 1, | 0, 0.W., (a) Find the constant c. (b) Find fx (x) and fy(y) (c) For 0 < x < 1, find fy|x=r(y) and My X=r and oỉ x=x (d) Find Cov(X,Y). (e) Are X and Y independent? Explain why.
Suppose X andY have joint density f(x,y)=6*x*y^2 for 0<x<1, 0<y<1. (a) What is P(X+Y ≤1)? (b) Compute the marginal densities fX , fY of X, Y .
question with answers, show steps: Given: fx,y(x,y)= (5/16)yx^2 for 0<y<x<2, determine: a) fx(x) by integrating y from 0 to x. Ans: fx(x)=(5/32)x^4 for 0<x<2 b) fy(y) by integrating x from y to 2 Ans: fy(y)=(5/48)y(8-y^3) for y<x<2 c) Test for independence using Criterion b Ans: Fails-> Not independent
Let (X, Y) have joint pdf given by f(r, y)= < a, 0 < < 0, О.w., (a) Find the constant c (b) Find fx(x) and fy(y) (c) For 0 x< 1, find fyx=r (y) and py|x=x and oyx= (d) Find Cov(X, Y) (e) Are X and Y independent? Explain why
The joint density of X and Y is given as f(x, y) = 4xy, 0 < x, 1 and 0 < y < 1. (a). Find the marginal distribution of Y, fY (y). (b). Find E[X|Y = 1/2]. (c). Find P(X < .3|Y < .2).
(50 points) Suppose that the joint p.d.f. of X and Y is as follows: for x 2 0, y 2 0, and x + y <1 elsewhere 2. 24xy f(x)0 a) Determine the value of P(X < Y). b) Determine the marginal p.d.f.'s for Xand Y c) Find P(X> 0.5) d) Determine the conditional p.d.f. of X|Y = 0.5 e) Find P(X> 0.5|Y 0.5) f) Find P(X> 0.5|Y> 0.5) g) Find Cov (X, Y)
The joint density function for X and Y is given as: f(x, y) = kxy for 0 < x < 2y < 1. Find the value of the constant k for which the p.d.f is legitimate. If the video does not work, click here to go to YouTube directly.