Assume that when adults with smartphones are randomly selected, 43% use them in meetings or classes. If 6 adult smartphone users are randomly selected, find the probability that at least 3 of them use their smartphones in meetings or classes.
Given data are sample n=6
P= 43% adults use smartphone in meetings or classes = 0.43
Then q=1-p=1-0.43 = 0.57
X= atleast 3 of them use smartphone in meetings or classes
In a binomial distribution p(x)= ncx
P ( atleast 3)= p (x 3) = 1- p (x <3)
= 1- [p (x=0) + p (x=1)+p (x=2)]
=1- [( ) + ()+()]
=1- [0.0343 + 0.1552 +0.2928]
= 1- 0.4823
=0.5177
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