4NO + 3Sb2O5+ 6H+6SbO+ + 4HNO3+ H2O In the above redox reaction, use oxidation numbers to...
4NO + 3Sb2O5+ 6H+6SbO+ + 4HNO3+ H2O
In the above redox reaction, use oxidation numbers to identify the
element oxidized, the element reduced, the oxidizing agent and the
reducing agent.
| name of the element oxidized: | name of the element reduced: | |||
| formula of the oxidizing agent: | formula of the reducing agent: | |||
Homework Answers
Sb in Sb2O5 has oxidation state of +5
Sb in SbO+ has oxidation state of +3
So, Sb in Sb2O5 is reduced to SbO+
This means Sb2O5 is oxidising agent
N in NO has oxidation state of +2
N in HNO3 has oxidation state of +5
So, N in NO is oxidised to HNO3
This means NO is reducing agent
Answer:
Name of element oxidised: Nitrogen
Name of element reduced: Antimony
Formula of the oxidising agent: Sb2O5
Formula of the reducing agent: NO
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