A marketing consultant is hired by a major restaurant chain wishing to investigate the preferences and spending patterns of lunch customers. The CEO of the chain hypothesized that the average customer spends at least $13.50 on lunch. A survey of 25 customers sampled at one of the restaurants found the average lunch bill per customer to be xbar = $14.50. Based on previous surveys, the restaurant informs the marketing manager that the standard deviation is σ=σ= $3.50. To address the CEO's conjecture, the marketing manager carried out a hypothesis test of H0:μ=H0:μ= $13.50, Ha:μ>Ha:μ> $13.50, and obtained a
P-value = 0.077. To illustrate his results, the director also wanted to calculate a 95% confidence interval with a margin of error m = $1.00. The required sample size equals:
A. |
30. |
|
B. |
100. |
|
C. |
25. |
|
D. |
48. |
A marketing consultant is hired by a major restaurant chain wishing to investigate the preferences and...
A marketing consultant is hired by a major restaurant chain wishing to investigate the preferences and spending patterns of lunch customers. The CEO of the chain hypothesized that the average customer spends at least $13.50 on lunch. A survey of 25 customers sampled at one of the restaurants found the average lunch bill per customer to be ?¯=$14.50 . Based on previous surveys, the restaurant informs the marketing manager that the standard deviation is ?=$3.50 . To address the CEO’s...