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A large volume of 0.150M Sulfurious Acid (H2SO3) is treated with a strong base to adjust...

A large volume of 0.150M Sulfurious Acid (H2SO3) is treated with a strong base to adjust the pH to 5.50. Assume that the additions of the base, a solid, does not significantly affect the volume of the solution. Estimate the molar concentration of H2SO3, HSO3(-), SO3 (2-) present in the final solution.

Ka1 = 1.5 x 10^-2 Ka2 = 1.2 x 10^-7

Answers are H2SO3 = .000032 M    HSO3(-)=.14 M SO3 (2-) = .0054 M

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