A flea jumps by exerting a force of Fflea = −1.54 ✕ 10−5 ĵ N straight down on the ground. A breeze blowing on the flea parallel to the ground exerts a force of Fwind = −7.12 ✕ 10−5 î + 2.38 ✕ 10−5 k N on the flea. Find the acceleration of the flea if its mass is 6.00 ✕ 10−7 kg. Express your answer in vector form. Assume that the +x axis is to the right, the +y axis is up along the page, and the +z axis is out of the screen towards you as shown in the figure below
Using Newton's 2nd law:
F_net = m*a
a = acceleration of flea = F_net/m
m = mass of flea = 6.00*10^-7 kg
F_net = F_flea + F_wind
Using given values:
F_net = (-1.54*10^-5 j) + (-7.12*10^-5 i + 2.38*10^-5 k)
F_net = (-7.12 i - 1.54 j + 2.38 k)*10^-5 N
So, acceleration will be:
a = F_net/m
a = (-7.12 i - 1.54 j + 2.38 k)*10^-5/(6.00*10^-7)
a = (-7.12/6.00 i - 1.54/6.00 j + 2.38/6.00 k)*10^2
a = (-1.187 i - 0.2567 j + 0.3967 k)*10^2 m/s^2
a = (-118.7 i - 25.67 j + 39.67 k) m/s^2
In three significant figures
a = (-119 i - 25.7 j + 39.7 k) m/s^2
Let me know if you've any query.
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