Question

Please show a clean way to organize and solve this problem so I can understand problem similar to it in the future

A flea jumps by exerting a force of 1.12 x 10-5 N straight down on the ground. A breeze blowing on the flea parallel to the ground exerts a force of 1.16 x 106 N on the flea. Find the direction and magnitude (in m/s2) of the acceleration of the flea if its mass is 6.0 × 10-7 kg. (Let us assume that i points to the right. We will consider this to be the +x direction and vertical to be the ty direction.) magnitude 1 wind Did you draw a free-body diagram, and identify the forces acting on the flea? Consider the forces acting on the flea during the time it is in contact with the ground. m/s2 direction2 o (measured clockwise from the vertical) e Tutorial

Answer 1

A)

Fy = (1.12 x 10^-6) - (6 x 10^-7 x 9.8) = 4.76 x 10^-6 N

Resultant, F = sqrt[(1.16 x 10^-6)^2 + (4.76 x 10^-6)^2] = 4.90 x 10^-6 N

Acceleration a = F/m = 8.17 m/s^2

B)

Direction, theta = arctan(1.16/4.76) = 13.70 degree