A random sample of small business stock prices has a sample mean of X = $54...
A random sample of small business stock prices has a sample mean of X = $54 82 and sample standard deviation of S = $8.95. Use the emperical rule to estimate the percentage of small business stock prices that are more than $81.67. round your answers to the nearest hundreth
Homework Answers
Add Answer to:
A random sample of small business stock prices has a
sample mean of X = $54...
A random sample of vehicle mileage expectancies has a sample mean of x¯=169,200 miles and sample...
A random sample of vehicle mileage expectancies has a sample mean of x¯=169,200 miles and sample standard deviation of s=19,400 miles. Use the Empirical Rule to estimate the percentage of vehicle mileage expectancies that are more than 188,600 miles. Round your answer to the nearest whole number (percent).
10. Stock Prices A random sample of stock prices per share (in dollars) is shown. Find...
10. Stock Prices A random sample of stock prices per share (in dollars) is shown. Find the 90% confidence interval for the variance and standard deviation for the prices. Assume the variable is normally distributed. Chapter 7 Confidence Intervals and Sample Size 404 3. Using Table G. find the values for en and icht a a0.05, n 12 b a 0.10,n-20 a0.05, n27 12.00 28.37 47.50 13.88 7.50 53.81 28.25 10.87 26.69 43.00 75.37 3.81 45.12 13.62 d a0.01,n=6 60.50...
1. Xis a normally distributed random variable with a mean of 12 and a standard deviation of 3. Calculate the probability that x equals 19.62. 2. A simple random sample of 8 employees of a corpora...
1. Xis a normally distributed random variable with a mean of 12 and a standard deviation of 3. Calculate the probability that x equals 19.62. 2. A simple random sample of 8 employees of a corporation provided the following information 25 32 26 54 22 23 Determine the point estimate for the average age of all employees. What is the point estimate for the standard deviation of the population? Determine a point estimate for the proportion of all employees who...
A random sample of 40 people who owned their own business reported a yearly mean profit...
A random sample of 40 people who owned their own business reported a yearly mean profit of $11,290 with a standard deviation of $1,251. Find the 92% confidence interval for the population mean. (Round your answers to the nearest dollar) Preview < μ< Preview What does this mean?
Stock Prices A random sample of stock prices per share (in dollars) is shown. Find the...
Stock Prices A random sample of stock prices per share (in dollars) is shown. Find the 95% confidence intervals for the variance and standard deviation for the prices. Assume the variable is normally distributed. Use a graphing calculator and round the answers to two decimal places. 14.75 46.12 10.87 40.25 60.50 28.00 28.25 6.94 45.12 13.62 53.81 3.81 43,00 47.50 7.50 75.37 12.00 28.37 Serdote State 247.549<o? < 948.13 15.3 <o< 30.79
A survey of 54 randomly selected "iPhone" owners showed that the purchase price has a mean...
A survey of 54 randomly selected "iPhone" owners showed that the purchase price has a mean of $400 with a sample standard deviation of $170. a. Compute the standard error of the sample mean. (Round the final answer to the nearest whole number.) Standard error b. Compute the 80% confidence interval for the mean. (Round the final answers to 2 decimal places.) The confidence interval is between $ and $ . c. How large a sample is needed to estimate...
Below is a sample of share prices (in dollars) for a particular stock, selected at random...
Below is a sample of share prices (in dollars) for a particular stock, selected at random over several years: 201 243 239 217 215 200 223 229 203 232 210 200 215 229 225 243 Use Excel (or another form of electronic assistance) to find the mean, median, mode, variance, standard deviation, and coefficient of variation for this sample. Make sure to add the numbers correctly! One simple mistake can cause several of your answers to be wrong. Mean =...
A simple random sample with n =54 provided a sample mean of 24.0 and a sample...
A simple random sample with n =54 provided a sample mean of 24.0 and a sample standard deviation of 4.5. a. develop a 90% CI for the pop mean b. develop a 95% CI for the pop mean c. develop a 99% CI for the pop mean d. what happens to the margin of error and the CI as the confidence level increases?
* The prices of pizzas can be described by a normal model with a mean of...
* The prices of pizzas can be described by a normal model with a mean of $12 and a standard deviation of $3. 12. Draw the model showing the 68-95-99.7 Rule 13. Use the 68-95-99.7 Rule to estimate the proportion of pizzas with prices between $12 and $18 14. Use the 68-95-99.7 Rule to estimate the proportion of pizzas with prices less than $9 15. Use the 68-95-99.7 Rule to estimate the proportion of pizzas with prices more than $21
Find the p-value for the hypothesis test. A random sample of size 54 is taken. The...
Find the p-value for the hypothesis test. A random sample of size 54 is taken. The sample has a mean of 426 and a standard deviation of 82. H0: µ = 400 Ha: µ > 400 The p-value for the hypothesis test is . Your answer should be rounded to 4 decimal places.
10. Stock Prices A random sample of stock prices per share (in dollars) is shown. Find the 90% confidence interval for the variance and standard deviation for the prices. Assume the variable is normally distributed. Chapter 7 Confidence Intervals and Sample Size 404 3. Using Table G. find the values for en and icht a a0.05, n 12 b a 0.10,n-20 a0.05, n27 12.00 28.37 47.50 13.88 7.50 53.81 28.25 10.87 26.69 43.00 75.37 3.81 45.12 13.62 d a0.01,n=6 60.50...
1. Xis a normally distributed random variable with a mean of 12 and a standard deviation of 3. Calculate the probability that x equals 19.62. 2. A simple random sample of 8 employees of a corporation provided the following information 25 32 26 54 22 23 Determine the point estimate for the average age of all employees. What is the point estimate for the standard deviation of the population? Determine a point estimate for the proportion of all employees who...
A random sample of 40 people who owned their own business reported a yearly mean profit of $11,290 with a standard deviation of $1,251. Find the 92% confidence interval for the population mean. (Round your answers to the nearest dollar) Preview < μ< Preview What does this mean?
Stock Prices A random sample of stock prices per share (in dollars) is shown. Find the 95% confidence intervals for the variance and standard deviation for the prices. Assume the variable is normally distributed. Use a graphing calculator and round the answers to two decimal places. 14.75 46.12 10.87 40.25 60.50 28.00 28.25 6.94 45.12 13.62 53.81 3.81 43,00 47.50 7.50 75.37 12.00 28.37 Serdote State 247.549<o? < 948.13 15.3 <o< 30.79
* The prices of pizzas can be described by a normal model with a mean of $12 and a standard deviation of $3. 12. Draw the model showing the 68-95-99.7 Rule 13. Use the 68-95-99.7 Rule to estimate the proportion of pizzas with prices between $12 and $18 14. Use the 68-95-99.7 Rule to estimate the proportion of pizzas with prices less than $9 15. Use the 68-95-99.7 Rule to estimate the proportion of pizzas with prices more than $21
Most questions answered within 3 hours.
-
Which of the following are true about the strength of the
association between two variables?
1-...
asked 30 seconds ago -
Raising a heavy load requires work. Raising it in half the time
requires:
asked 5 minutes ago -
Calculate the number of valence electrons for
[Mo(C6H6)(CO)3]
asked 3 minutes ago -
MGT-201: Marketing Management
Before deciding on the structure of the channel marketers must
take several factors...
asked 5 minutes ago -
1. ACLs allow a router to control traffic within a network. The
concept is very similar...
asked 7 minutes ago -
35. When the electron in a hydrogen atom falls from its first
excited energy level to...
asked 8 minutes ago -
A man is dragging a box of mass "m" by using a rope which rests
on...
asked 24 minutes ago -
Liquid octane
(CH3(CH2)6CH3) will
react with gaseous oxygen (O2) to produce gaseous carbon
dioxide (CO2) and...
asked 26 minutes ago -
For the reaction N2(g) +
O2(g) --> 2NO(g), if the initial
concentration of NO was 0.00M...
asked 29 minutes ago -
On a recent quiz, the class mean was 75 with a standard
deviation of 2.2. Calculate...
asked 45 minutes ago -
Discuss the Coefficient of Restitution in an elastic collision
compared to the Coefficient of Restitution in...
asked 49 minutes ago -
Pretend that you are
the audit manager on an annual financial statement audit engagement
for a...
asked 58 minutes ago