Starting with an initial speed of 3.76 m/s at a height of 0.469 m, a 1.52-kg...
Starting with an initial speed of 3.76 m/s at a height of 0.469 m, a 1.52-kg ball swings downward and strikes a 5.52-kg ball that is at rest, as the drawing shows. (a) Using the principle of conservation of mechanical energy, find the speed of the 1.52-kg ball just before impact. (b) Assuming that the collision is elastic, find the velocity (magnitude and direction) of the 1.52-kg ball just after the collision. (c) Assuming that the collision is elastic, find the velocity (magnitude and direction) of the 5.52-kg ball just after the collision. (d) How high does the 1.52-kg ball swing after the collision, ignoring air resistance? (e) How high does the 5.52-kg ball swing after the collision, ignoring air resistance?
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Starting with an initial speed of 3.76 m/s at a height of 0.469
m, a 1.52-kg...
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As shown in the figure below, object m1 = 1.55 kg starts at an initial height h1i = 0.325 m and speed v1i = 4.00 m/s, swings downward and strikes (in an elastic collision) object m2 = 4.55 kg which is initially at rest.
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A truck with a mass of 1710 kg and moving with a speed of 14.0 m/s rear-ends a 613 kg car stopped at an intersection. The collision is approximately elastic since the car is in neutral, the brakes are off, the metal bumpers line up well and do not get damaged. Find the speed of both vehicles after the collision in meters per second. m/s truck m/s car As shown in the figure below, object m, = 1.50 kg starts...
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