If a 0.01 M Mn(NO3)2 solution has an ammonia concentration of 6.0 M, should a precipitate of Mn(OH)2 form? Calculate the ion product (reaction quotient) and compare it to Ksp to support your answer.
NH3 concentration = 6.0 M
Kb = 1.8 x 10^-5
[OH-] = sqrt (Kb x C )
= sqrt (1.8 x 10^-5 x 6.0)
= 0.0104 M
Q = [Mn2+][OH-]^2
Q = (0.01 ) (0.0104)^2
ionic product = Q = 1.08 x 10^-6
Ksp of Mn(OH)2 = 4.6 x 10^-14
Q > Ksp
so precipitate will be formed
If a 0.01 M Mn(NO3)2 solution has an ammonia concentration of 6.0 M, should a precipitate...
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