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A chain restaurant wants to estimate the population mean weight of one of their entrees. A...

A chain restaurant wants to estimate the population mean weight of one of their entrees. A random sample size n = 36 showed sample mean = 18 ounces with sample standard deviation s = 1.8 ounces. Create a confidence interval at 95% confidence for the population mean μ.
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Answer #1

n = 36

μ = 18

σ = 1.8

For 95% confidence and degree of freedom = 36 -1 = 35

t = 2.0301

confidence interval

= μ ± (t * σ / √n )

= 18 ± ( 2.0301 * 1.8 / √36)

= 18 ± 0.60903

= ( 17.39097 , 18.60903 )

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