Question

The midterm scores for undergraduate statistics students were distributed as a normal distribution and they had...

The midterm scores for undergraduate statistics students were distributed as a normal distribution and they had the following statistics: a mean of 88 and a standard deviation of 4.

If 2 extra points were added to each student's score, the mean is _____ and the standard deviation is _____.

If all scores were increased by 25%, the mean is _____ and the standard deviation is _____.

0 0
Add a comment Improve this question Transcribed image text
Know the answer?
Add Answer to:
The midterm scores for undergraduate statistics students were distributed as a normal distribution and they had...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • The scores on a statistics exam had an approximately normal distribution, with a mean of 73...

    The scores on a statistics exam had an approximately normal distribution, with a mean of 73 and standard deviation of 7.2. If a single student is chosen at random, what is the probability their score is less than 74?

  • 1. Ms. Jackson has three sections of the course "Introduction to Statistics.” The midterm results reveal...

    1. Ms. Jackson has three sections of the course "Introduction to Statistics.” The midterm results reveal that class A has an average of 82, class B has an average of 88, and class C has an average of 92. If there were 20 students in class A, 25 students in class B, and 27 students in class C, what is the combined mean (the average for all the three classes)? Show your work. 2. In your Biology class, your final...

  • Solve the problem. 4) 4) The midterm and final exam scores of 10 students in a statistics course ...

    Solve the problem. 4) 4) The midterm and final exam scores of 10 students in a statistics course are observed and re in variable X and Y. The observed data yield (a) Find a (b) Find B. (c) Calculate the least squares regression line frormthese data. (d) If a student's midterm score is 75, what is his predicted final exam score? (e) If one has calculated σ-18, what is the 95% confidence interval for Y when the studen midtern score...

  • (a) In 2000, the scores of students taking SATs were normally distributed with mean 1019 and...

    (a) In 2000, the scores of students taking SATs were normally distributed with mean 1019 and standard deviation 209. (i) What percent of all students had the SAT scores of at least 820? [3 marks] (ii) What percent of all students had the SAT scores between 720 and 820? [3 marks] (iii) How high must a student score in order to place in the top 20% of all students taking the SAT? [4 marks]

  • If the SAT scores of students in a high school follow the normal distribution with mean...

    If the SAT scores of students in a high school follow the normal distribution with mean = 1200 and standard deviation = 100, what is the probability that a randomly selected student's score is between 1000 and 1400? OA 0.9973 B. 0.9545 OC. 0.9999 OD. 0.6827 Reset Selection

  • Example 3 The scores on a midterm exam follow a normal distribution with an average of...

    Example 3 The scores on a midterm exam follow a normal distribution with an average of 80.4% and a standard deviation of 10.9%. Let X represent the score of a given student on this midterm exam. 1. What is the probability that a randomly selected student scores above a 90%? 2. What is the probability that a randomly selected student scores between 80% and 90%? 3. What is the 60th percentile score for this midterm exam?

  • The scores of students on the SAT college entrance examinations at a certain high school had...

    The scores of students on the SAT college entrance examinations at a certain high school had a normal distribution with mean ?=537μ=537 and standard deviation ?=27.5σ=27.5. (a) What is the probability that a single student randomly chosen from all those taking the test scores 542 or higher? ANSWER: For parts (b) through (d), consider a simple random sample (SRS) of 25 students who took the test. (b) What are the mean and standard deviation of the sample mean score ?¯x¯,...

  • Scores on a recent national statistics exam were normally distributed with a mean of 88 and...

    Scores on a recent national statistics exam were normally distributed with a mean of 88 and a standard deviation of 2. 1. What is the probability that a randomly selected exam will have a score of at least 85? 2. What percentage of exams will have scores between 89 and 92? 3. If the top 5% of test scores receive merit awards, what is the lowest score eligible for an award? I do not understand how to compute probability.

  • if statistics test scores were normally distributed with a mean of 81 and a standard deviation...

    if statistics test scores were normally distributed with a mean of 81 and a standard deviation of 4, a) what is the probability that a randomly selected student scored less than 70? b) what percentage of students had a B on the exam? c) the top 10% of the class had what grades?

  • The scores of students on the SAT college entrance examinations at a certain high school had...

    The scores of students on the SAT college entrance examinations at a certain high school had a normal distribution with mean μ=553.3 and standard deviation σ=28.6.Round z-scores to 2 decimal places and give probabilities to 4 decimal places. (a) What is the probability that a single student randomly chosen from all those taking the test scores 558 or higher? ANSWER: For parts (b) through (d), consider a simple random sample (SRS) of 30 students who took the test. (b) What...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT