the energy is required to remove an electron from the K shell can be,
Ek = ( Z - 1 )2 Eo
here Eo = 13.6 eV
= ( 46 - 1 )2 x 13.6
= 452 x 13.6
= 2025 x 13.6
Ek = 27540 eV
so the photon energy in keV for tungsten is Ek = 27.540 keV.
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