If 5.03 g of Ethylene Glycol are added to 96.6 g of water what is the freezing point of the solution
first calculate molality of solution
molality = (W /MW) (W / mass of solvent g)
molality = (5.03 / 62.07) ( 1000 / 96.6)
molality = 0.84 M
now
Tf = Kf x m
Kf = 1.86 0C / m
Tf = 1.86 x 0.84
Tf = 1.56
Tf = 0 - 1.56
Tf = - 1.56 0C
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