A bicycle tire registers 90 psi (14.7 psi = 1 atm). What is that in torr?
14.7 psi = 1 atm
90 psi = 90 / 14.7 = 6.12 atm
we know,
1 atm = 760 torr
and
6.12 atm = 6.12 * 760 = 4653 torr = 4.65 * 10^3 torr (answer)
A bicycle tire registers 90 psi (14.7 psi = 1 atm). What is that in torr?
An automobile tire is inflated to a pressure of 31.4 psi. What is the pressure in torr? Hint: 1 atm = 760 torr = 14.7 psi A 351000 torr B 0.607 torr C 1.65 torr D 1620 torr E 0.0281 torr
Given 1 atm = 760 torr = 760 mmHg = 14.7 psi. A balloon sample of helium has a volume of 550 mL at a pressure of 1.0 atm. a. Assuming no change in temperature or amount of helium, what is the new volume in mL if pressure drops to 8.5 psi? b. Assuming no change in temperature or amount of helium, what is the new pressure in mmHg if volume expands to 650 mL?
A motorist discovers that her auto tire measures 14.7 psi rather than the recommended 29.4 psi. If the tire’s volume is assumed constant at 22.4 L and the temperature is 0 degrees Celsius at the filling station, how many moles of air will the motorist need to add to bring the tire to 29.4 psi? (assume 1.00 atm= 14.7 psi)
(10 points) The air pressure within the bicycle tire is determined from a gage to be 45.5 psi. If the local atmospheric pressure is 14.7 psi, determine the absolute pressure in the tire. Report answer in psi. 1.
A gas sample has a pressure of 1.30 atm. What is this pressure in torr? Hint: 1 atm = 101.3 kPa = 1.013 bar = 760 torr = 760 mm Hg = 14.7 psi torr
A tire at 32 PSI at 37oC is left outside and the temperature drops to 10oC overnight. What is the pressure in the tire at the new temperature? 1 atm = 14.7 lb/in2
19. 19. Which of these is the lowest pressure? (1 atm = 14.7 psi = 29.92 in.Hg = 101.325 kPa = 760 Torr) A. 0.87 atm B. 21 in.Hg C. 420 Torr D. 12 psi E. 63 kPa (kiloPascal) om law? 22. 22. Which equation is an invalid representation of the combined gas Assume that Ti and T2 are in Kelvin units. For a given quantity of gas, A. TV,P1 = T:V2P2 B. V.T2/P2 = V2T/P C. T./(V.P.) = T2/(V2P2)...
An automobile tire is inflated to a pressure of 31.2 psi. Express this pressure in atmospheres, kilopascals, inches Hg, millimeters Hg and torr. Hint: 1 atm = 101.3 kPa = 29.92 in Hg = 760 mm Hg = 14.69 psi = 760 torr psi atm kPa in Hg mm Hg torr 31.2
1. A 1.35 L bicycle tire is inflated to 60 PSI. How many liters of air at standard pressure are in the tire ?
Can someone help me with these conversions? psi 35.6 psi atm mmHg torr 1.45 atm 832 mmHg 654torr