Question

Part D. On executing the below program, what will be the output of the following program if the source file contains a line "This is a sample."? [5 marks]

#include <stdio.h>

int main()

{ char ch;

int k, n=0;

FILE * fs = fopen("source.txt", "r");

while(1) {

ch = fgetc(fs);

if(ch == EOF) break;

else { for(k=0;k<4;k++)

fgetc(fs);

printf("%c", ch);

n += k; }

}

printf("%d\n", n);

fclose(fs);

return 0;

}

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Any one can explain the question to me including the output(not only the output)? many thanks

Answer 1

#include <stdio.h>

int main()
{
char ch; // character variable ch for holding character value
int k, n=0; // integer type variable declaration with n initialized with 0
FILE * fs = fopen("source.txt", "r"); //file type pointer fs which holds file status in fs pointer variable , file name source.txt in read mode
while(1) //while there is a content in the file keep reading
{
ch = fgetc(fs); //get first character from file pointer fs and copy in ch
if(ch == EOF) break; // if ch is end of file character then terminate program
else
{
for(k=0;k<4;k++) // else print 4 character from file
fgetc(fs); // read from fs variable
printf("%c",fs);
printf("%c", ch); // print character variable content on screen
n += k; // increment counter of n which is initialized 0 above
}
}
printf(" %d \n ", n); // print value of n
fclose(fs);
return 0;
}

WHAT EVER THE CHARACTER CONTAINS IN THE FILE +1 WILL BE THE VALUE OF VARIABLE N AT THE LAST AND CH VARIABLE FETCH FIRST CHARACTER OF THE NEW WORD AS I HAVE CAPITALIZE THAT EACH CHARACTER WHICH IT READS.

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