Question

int c = 75;

int d = 100;

int& r1 = c;

int& r2 = d;

c++;

r2++;

Use the code above. Suppose the variable c lives at memory address 512, and d lives at the memory address 1024. The size of an integer is 4 bytes. After execution of the above code, draw labelled boxes for each of the 4 variables c, d, r1 and r2, and show their integer values. For r1 and r2, draw an additional arrow to where it points. Include addresses of boxes where applicable.

int w = 1;

int x = 2;

int* f = &w;

int* g = &x;

int y = 3;

int z = 4;

int& h = y;

int& i = z;

f = g;

h = i;

Draw labelled boxes for each of the 8 variables, and after execution of the above code show the contents of each box. Assume w lives at memory address 128, x lives at 256, y lives at 512, and z lives at 1024. In addition, draw arrows from f, g, h and i to where they point. Include addresses of boxes where applicable.

Answer 1

A reference variable is an alias, that is, another name for an already existing variable. A reference, like a pointer, is also implemented by storing the address of an object.A reference can be thought of as a constant pointer (not to be confused with a pointer to a constant value!) with automatic indirection, i.e the compiler will apply the * operator for you. A reference shares the same memory address (with the original variable) but also takes up some space on the stack.

#include <iostream>
using namespace std;
int main()
{
int c = 75;
int d = 100;
int& r1 = c;
int& r2 = d;
c++;
r2++;
cout<<c<<"\n";
cout<<r2;
   return 0;
}

OUTPUT:

76

101

#include <iostream>
using namespace std;
int main()
{
int w = 1;
int x = 2;
int* f = &w;
int* g = &x;
int y = 3;
int z = 4;
int& h = y;
int& i = z;
f = g;
h = i;
cout<<f<<"\n";
cout<<g<<"\n";
cout<<h<<"\n";
cout<<i<<"\n";
return 0;
}

OUTPUT: 1

0x7fffe1f28f78
0x7fffe1f28f78
4
4

OUTPUT: 2

0x7ffeffa9e1c8
0x7ffeffa9e1c8
4
4

Kindly like my answer.