A coin is tossed 16 times. In how many outcomes do at most 2 tails occur?
a) 136 b) 137 c) 65,416 d) 65,399
Combination formula: nCr = n!/(r! x (n-r)!)
Number of outcomes with 0 tails = 16C0 = 1
Number of outcomes with 1 tail = 16C1 = 16
Number of outcomes with 2 tails = 16C2 = 120
Number of outcomes with at most 2 tails occur = 1 + 16 + 120
= 137
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