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Using ONLY logical equivalences (not truth tables!), prove for the following that one element of the...

Using ONLY logical equivalences (not truth tables!), prove for the following that one element of the pair is logically equivalent to the other one using logical equivalences (ex. De Morgan's laws, Absorption laws, Negation laws etc.)

a) ~d -> (a && b && c) = ~(~a && ~d) && ((d || b) & (c || d))

b) (a->b) && (c->d) = (c NOR a) || (b && ~c) || (d && ~a) || (b && d)

c) (~a && ~b) <--> (c || d) = (a || b || c || d) && ~((a || b) && (c || d))

d) (a XOR b) -> (~c XOR d) = ((a NOR b) || (a && b)) || ((c NOR d) || (c && d))

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