Flux density of magnetic field B around a current carrying wire is given by,
Hence flux density of magnetic field at a radial distance r,
B(r) = ( I ) / ( 2 r) .............(1)
For magnetic field inside wire, current I is calculated as shown below
Let us consider the cross section of wire as shown in figure. Current I is uniformly distributed
Current passing through the cross section of radius r is obtained as
where j is current density across the area of cross section, j = I / (a2)
since a = 1, current passing through the cross section of radius r in side wire ( r < a ) is given by
Ir = (1/)r2 = r2
Hence flux density of magnetic field inside wire ,
B(r) = [ ( ) / ( 2 r) ] r2 = [ / (2) ] r , .......r a
Flux density of magnetic field outside the wire,
B(r) = [ / (2 r) ] ........ r > a
Plot of flux density of magnetic field is given below
Derive the magnetic field B inside and outside of an infinite thick wire with radius a=1....
The long, thin wire shown in the figure (Figure 1) is in a region of constant magnetic field B⃗ . The wire carries a current of 6.2 A and is oriented at an angle of 7.5° to the direction of the magnetic field. A) If the magnetic force exerted on this wire per meter is 3.3×10-2 N , what is the magnitude of the magnetic field? B) At what angle will the force exerted on the wire per meter be equal to...
TA) Q4: Time (30 minutes) A. The current flowing in a solenoid, of 400 turns, 20 cm length & 4 cm diameter, changes with time according to the graph show to right. Derive an expression for the strength of the induced electric field inside the solenoid 0 00 01 02 03 04 Sketch the corresponding graph showing how the induced electric field vary with time. B. The Figure to right shows an infinite straight wire carries a current I is...