Cora wants to determine a 95% confidence interval for the true proportion of high school students...
Cora wants to determine a 95% confidence interval for the true proportion of high school students in the area who attend their home basketball games. How large of a sample must she have to get a margin of error less than 0.03?
Homework Answers
Solution,
Given that,
= 1 -
= 0.5
margin of error = E = 0.03
At 95% confidence level
= 1 - 95%
= 1 - 0.95 =0.05
/2
= 0.025
Z/2
= Z0.025 = 1.96
sample size = n = (Z
/ 2 / E )2 *
* (1 -
)
= (1.96 / 0.03 )2 * 0.5 * 0.5
= 1067.11
sample size = n = 1068
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