To obtain a resolution of 1.50, how many theoretical plates must a packed column have for two peaks which elute at 5.42 and 5.63 minutes, where tm = 1.00 min? With a resolution of 1.50, are these peaks considered to be resolved?
Now the equation that relates resolution (Rs) of a column with therotical plates (N) is
Rs = [[(tR)B - (tR)A ] X square root of(N)] / [(tR)B X 4]
where (tR)B = retention time of peak B here 5.63 min
( tR )A = retention time of peak A here 5.42 min
Rs = resolution = 1.5
N =theoritical plates = ?
putting these values in above equation
1.5 = [(5.63 - 5.42) X square root of(N)] / (5.63 X 4)
N = 23875.02
if Rs = 1.0 it is considered to be adequate most of the separations so here at resolution 1.5 these peaks considered to be well resolved
To obtain a resolution of 1.50, how many theoretical plates must a packed column have for...
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