Question

Speeding Fine Calculator

You have been hired by the police department of the city you live in to create a program to calculate the fine that a motorist could pay. If the motorist was travelling at or below the speed limit, there is no fine. If the motorist is travelling over the speed limit, the amount of the fine is determined based on the table below. The speed limit that will be entered is a multiple of 5 from 5 to 85.

For example, if the speed limit was 30 and the speed measured was 34, the motorist was travelling 13.33% [ (34 - 30) / 30 ] over the speed limit. From the table, a motorist travelling 13.33% over the speed limit of 30 is liable for a fine of $180.

	Percentage over Speed Limit
Speed Limit	Less than 5%	5% - Less than 10%	10% - Less than 25%	25% or more
25 or lower	70	85	120	180
26 - 45	85	120	180	250
46 - 65	100	150	200	300
Over 65	150	200	300	500

The program will prompt for the speed limit and the actual speed the motorist was measured travelling. When the information is entered, the program will determine whether a fine is due or not and if a fine is due, what the fine amount is. The posted speed limit will always be a whole number.

Write pseudocode for the program and then code the pseudocode using the Python programming

• Pseudocode file (e.g. speedingfinecalculator.txt)
• Python program (e.g. speedingfinecalculator.py

Answer 1

#include<stdio.h>

void main()

{

int speed,i,limit=30,per;

printf("Enter speed : ");

scanf("%d",&speed);

if(speed<limit)

{

printf("No Fine");

}

else

{

per=(speed-limit)/limit;

}

if(speed<25)

{

if(per<5)

printf("Fine = 70");

else if(per>5 && per<10)

printf("Fine = 85");

else if(per>10 && per<25)

printf("Fine = 120");

else if(per>25)

printf("Fine = 180");

}

else if(speed>25 && speed<45)

{

  if(per<5)

printf("Fine = 85");

else if(per>5 && per<10)

printf("Fine = 120");

else if(per>10 && per<25)

printf("Fine = 180");

else if(per>25)

printf("Fine = 250");

}

else if(speed>45 && speed<65)

{

if(per<5)

printf("Fine = 100");

else if(per>5 && per<10)

printf("Fine = 150");

else if(per>10 && per<25)

printf("Fine = 200");

else if(per>25)

printf("Fine = 300");

}

else if(speed>65)

{

if(per<5)

printf("Fine = 150");

else if(per>5 && per<10)

printf("Fine = 200");

else if(per>10 && per<25)

printf("Fine = 300");

else if(per>25)

printf("Fine = 500");

}

}