For the following reaction: 3O2(g) ------> 2O3(g) delta H= 285.4kJ Will the reaction be spontaneous, nonspontaneous,...

Question

Question

For the following reaction: 3O2(g) ------> 2O3(g) delta H= 285.4kJ

Will the reaction be spontaneous, nonspontaneous, or impossible to determine at standard conditions. Briefly explain your answer.

Answer 1

Answer #1

ΔHo is positive as given in question

ΔSo is negative because reactant has more number of gases as compared to product.

Use:

ΔGo = ΔHo - T*ΔSo

ΔGo will always be positive irrespective of temperature.

So, the reaction is non spontaneous

Answer: spontaneous

Answer 2

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