At the local county fair, you watch as a blacksmith drops a 0.520-kg iron horseshoe into a bucket containing 26.5 kg of water. If the initial temperature of the horseshoe is 454°C, and the initial temperature of the water is 23.1°C, what is the equilibrium temperature of the system? Assume no heat is exchanged with the surroundings. Do not enter unit.
b) Suppose the 0.520-kg iron horseshoe had been a 1.07-kg lead horseshoe instead. What would the equilibrium temperature be in this case? Do not enter unit.
Heat lost = heat gain
m x c (Tf- Ti) = m' x c' x ( Tf - Ti)
0.52 x449 x ( 454 - T) = 26.5 x 4200 x ( T - 23.1)
T= 24 C
For lead
1.07 x 129 x (454 - T) = 26.5 x 4200x ( T- 23.1)
T = 23.63 C
At the local county fair, you watch as a blacksmith drops a 0.520-kg iron horseshoe into...
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