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If both husband and wife are known to be heterozygous for the autosomal recessive condition of...

If both husband and wife are known to be heterozygous for the autosomal recessive condition of albinism, what is the probability that among their four children, three will be normal and one will have albinism?

I know that each child has a 3/4 probability of being normal and 1/4 probability of having albinism. So is the answer 3/4 * 3/4 * 3/4 * 1/4? Or do you just do 3/4 * 3/4 * 3/4?

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