What is the value of ΔHrxn if the reaction below is reversed? In other words, PCl5 becomes the reactant. Report your answer in kJ to 1 decimal place.
PCl3(g) + Cl2(g) → PCl5(g); ΔHrxn = -211.4
What is the value of ΔHrxn if the reaction below is reversed? In other words, PCl5...
What is the value of AHpxn if the reaction below is reversed? In other words, PCi5 becomes the reactant. Report your answer in kJ to 1 decimal place. PC13(g) + Cl2(g) – PC15(g); AHpx = -81.4 What is the enthalpy of reaction, AHrxn for the reaction of nitrogen gas with oxygen gas to produce NO2(g), based on the following information? These reactions are not at standard state or at 298 K. • N2(g) + O2(g) 2 NO(g); AH = -240.6...
An analysis of a chemical reaction system at 340 °C shows that PCl5, PCl3, and Cl2 are present at equal concentrations of 0.120 mol/L. Determine the equilibrium concentrations (in M) of PCl5, PCl3 and Cl2 at 340 °C, given that Kc = 0.800. Show all calculations and report your answer to the correct number of sig figs. PCl5(g) ⟺ PCl3(g) + Cl2(g)
In the equation below, PCl3(g) + Cl2(g) « PCl5(g) the forward reaction is first order in both PCl3 and Cl2 and the reverse reaction is first order in PCl5. (a) Suppose that 2 moles of PCl3 and 1 mole of Cl2 are mixed in a closed 1.0 L container at constant temperature. Draw a graph that shows how the concentrations of PCl3, Cl2, and PCl5 change with time until after equilibrium has been firmly established. Indicate the numerical values on...
Consider the following reaction: PCl5(g)⇌PCl3(g)+Cl2(g) a. Initially, 0.62 mol of PCl5 is placed in a 1.0 L flask. At equilibrium, there is 0.20 mol of PCl3 in the flask. What is the equilibrium concentration of PCl5? Express your answer to two significant figures and include the appropriate units. b. What is the equilibrium concentration of Cl2? Express your answer to two significant figures and include the appropriate units. c. What is the numerical value of the equilibrium constant, Kc, for...
Consider the reaction. PCl5(g)−⇀↽−PCl3(g)+Cl2(g)Kc=0.0420 The concentrations of the products at equilibrium are [PCl3]=0.180 M and [Cl2]=0.280 M. What is the concentration of the reactant, PCl5, at equilibrium?
Consider the reaction. PCl5(g)↽−−⇀PCl3(g)+Cl2(g)?c=0.0420 The concentrations of the products at equilibrium are [PCl3]=0.120 M and [Cl2]=0.150 M. What is the concentration of the reactant, PCl5, at equilibrium?
Consider the reaction. PCl5(g)↽−−⇀PCl3(g)+Cl2(g)?c=0.0420 PCl 5 ( g ) ↽ − − ⇀ PCl 3 ( g ) + Cl 2 ( g ) K c = 0.0420 The concentrations of the products at equilibrium are [PCl3]=0.270 M [ PCl 3 ] = 0.270 M and [Cl2]=0.180 M [ Cl 2 ] = 0.180 M . What is the concentration of the reactant, PCl5 PCl 5 , at equilibrium? [PCl5]= [ PCl 5 ] =
What are the equilibrium partial pressures of PCl3, Cl2, and PCl5, respectively?Express your answers numerically in atmospheres with three digits after the decimal point, separated by commas.An Equilibrium Study: Phosphorus Trichloride/Phosphorus Pentachloride EquilibriumFor the exothermic reactionPCl3(g)+Cl2(g)→PCl5(g)Kp = 0.180 at a certain temperature.A flask is charged with 0.500 atm PCl3 , 0.500 atm Cl2, and 0.300atm PCl5 at this temperature.
For the reaction PCl5(g) <-->PCl3(g) + Cl2(g) the value of K = 28.3 at 532.0 K. Calculate the equilibrium partial pressures (in bar) of all species at 532.0 K if the initial pressures were P(PCl5(g)) = 0.664 bar, P(PCl3(g)) = 0.326 bar, and P(Cl2(g)) = 0.000 bar.
For the reaction PCl5(g) ↔ PCl3(g) + Cl2(g) the value of K = 15.4 at 497.0 K. Calculate the equilibrium partial pressures (in bar) of all species at 497.0 K if the initial pressures were P(PCl5(g)) = 0.700 bar, P(PCl3(g)) = 0.320 bar, and P(Cl2(g)) = 0.000 bar.