If 1.92 mL of a 0.335 M NaOH solution were required to completely neutralize an acid...

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If 1.92 mL of a 0.335 M NaOH solution were required to completely neutralize an acid...

If 1.92 mL of a 0.335 M NaOH solution were required to completely neutralize an acid solution, what was the total number of moles of base dispensed? Make sure you have the correct number of significant figures. Do not include the units in your answer.

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Answer 1

Answer #1

Given 1.92 ml of 0.335 M of NaOH was required to completely neutralize the acid solution.

So as NaOH is base so moles of NaOH is given by

Moles of NaOH = Volume in litres*Molarity

So,Moles of NaOH=(1.92/1000)*0.335=0.000643 moles

So,answer is 0.000643 (upto 3 significant figures)

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Answer 2

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If 1.92 mL of a 0.335 M NaOH solution were required to completely neutralize an acid...

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