A particle of mass M = 0.60 kg is dropped from a point that is at...
A particle of mass M = 0.60 kg is dropped from a point that is at a height h = 3.00 m above the ground and horizontal distance s = 0.65 m from an observation point O, as shown in the figure. What is the magnitude of the angular momentum of the particle with respect to point O when the particle has fallen half the distance to the ground? (kg*m^2/s)
Homework Answers
Apply conservation of energy
mgh = 1/2 * mv^2
v= sqrt 2gh
= sqrt 2 (9.8)(3/2)
=5.42 m/s
L= mvr = 0.6 (5.42) (0.65) = 2.11 kg m^2/s
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