A population of rabbits oscillates 19 above and below an average of 124 during the year, hitting the lowest value in January (t = 0). Find an equation for the population, P, in terms of the months since January, t. P ( t ) P(t) = What if the lowest value of the rabbit population occurred in April instead? P ( t ) P(t) =
A population of rabbits oscillates 19 above and below an average of 124 during the year,...
A population of rabbits oscillates 31 above and below average during the year, hitting the lowest value in January (t = 0). The average population starts at 800 rabbits and increases by 9% each month. Find an equation for the population, P, in terms of the months since January, t.
A population of rabbits oscillates 27 above and below average during the year, hitting the lowest value in January (t = 0). The average population starts at 900 rabbits and increases by 180 each year. Find an equation for the population, P, in terms of the months since January, t.
A population of rabbits oscillates 20 above and below average during the year, hitting the lowest value in January (t = 0). The average population starts at 950 rabbits and increases by 8% each month. Find an equation for the population, P, in terms of the months since January, t.
Du Find a possible formula for the trigonometric function whose values are in the following table. 4. 0 1 8 - 7 12 16 20 24 -3 -7 у -3 -3 1 Preview Get help: Video Video A population of rabbits oscillates 25 above and below an average of 80 during the year, hitting the lowest value in January (t = 0). Find an equation for the population, P, in terms of the months since January, t. P(t) - Preview...
1. Outside temperature over a day can be modeled as a sinusoidal function. Suppose you know the high temperature for the day is 82 degrees and the low temperature of 68 degrees occurs at 3 AM. Assuming t is the number of hours since midnight, find an equation for the temperature, D, in terms of t. D(t)= 2. A population of rabbits oscillates 18 above and below an average of 62 during the year, hitting the lowest value in January...
A population of rabbits is at its lowest in January (t=0) and oscillates 27 above and below an average of 97 during the year.What is the population of rabbits in September?95 rabbits120 rabbits111 rabbits124 rabbitsNone of these answers are correct.
Population Growth: Let P(t) be the number of rabbits in the rabbit population. In the simplest case we can assume the number of rabbits born at any moment of time is proportional to the number of rabbits at this moment of time. Mathematically we can write this as a differential equation: Here b is the birth rate, i.e. births per time unit per rabbit. In the model above we ignore deaths and assume resources are unlimited. A. Solve the equation...
21² + 6 Ay The population, P, in thousands of a resort community is given 100 600t by P(t) = t20, where t is time, in months. 80-A a) Find the population at t= 0, 1, 3, and 8 months. .60 b) Find the horizontal asymptote of the graph and determine the 401 value that P(t) approaches as t goes to co? c) Explain the meaning of the answer to part (b) in terms of the 20- application 0 10...
1) Please write clearly and complete all parts. Thank You. Ay 80- a 60- The population, P, in thousands, of a resort community is given 100+ 700t by P(t) = t20, where t is time, in months. 6t? +4 a) Find the population at t= 0, 1, 3, and 8 months. b) Find the horizontal asymptote of the graph and determine the 404 value that P(t) approaches as t goes to ? c) Explain the meaning of the answer to...
Following are the transactions and adjustments that occurred during the first year of operations at Kissick Co. Issued 198,000 shares of $4-par-value common stock for $792,000 in cash. Borrowed $520,000 from Oglesby National Bank and signed a 10% note due in three years. Incurred and paid $410,000 in salaries for the year. Purchased $730,000 of merchandise inventory on account during the year. Sold inventory costing $570,000 for a total of $900,000, all on credit. Paid rent of $330,000 on the...