In the solution below at first i have shown the derivation of the expression for velocity v and then using the expression i solved for angle θ. If you are familar with the derivation jump directly to the solution.
Derivation of v
Solving for angle θ
A truck is taking a curve of radius of 200 m and sees the road sign...
A car rounds a curve that is banked inward. The radius of curvature of the road is R = 142 m, the banking angle is θ = 30°, and the coefficient of static friction is μs = 0.32. Find the minimum speed that the car can have without slipping. I got 36.5196 m/s, which isn't correct.
A car rounds a curve that is banked inward. The radius of curvature of the road is R = 140 m, the banking angle is θ = 26°, and the coefficient of static friction is μs = 0.39. Find the minimum speed that the car can have without slipping. A car rounds a curve that is banked inward. The radius of curvature of the road is R 140 m, the banking angle is 26e, and the coefficient of static minimum...
A car rounds a curve that is banked inward. The radius of curvature of the road is R = 152 m, the banking angle is θ = 32°, and the coefficient of static friction is μs = 0.23. Find the minimum speed that the car can have without slipping.
A curve with a 130 m radius on a level road is banked at the correct angle for a speed of 20 m/s. If an automobile rounds this curve at 30 m/s, what is the minimum coefficient of static friction between tires and road needed to prevent skidding?
The flatbed truck starts from rest on a road whose constant radius of curvature is 38 m and whose bank angle is 8° Ifthe constant forward acceleration of the truck is 2.5 m/sec2, determine the smallest time t after the start of motion at which the crate on the bed begins to slide. The coefficient of static friction between the crate and truck bed is μ.-11 , and the truck motion occurs in a horizontal plane sec
Q5: A flatbed truck starts from rest on a road whose constant radius of curvature is 30 m and whose bank angle is 1°. If the constant forward acceleration of the truck is 2 m/s, determine the time t after the start of motion at which the crate on the bed begins to slide. The coefficient of static friction between the crate and truck bed is -0.3, and the truck motion occurs in a horizontal plane. (5.58 s 10°
Banked curves are designed so that the radial component of the normal force on the car rounding the curve provides the centripetal force required to execute uniform clrcular motion and safely negotlate the curve. A car rounds a banked curve with banking angle θ-27.1° and radius of curvature 157 m. (a) It the coefficient of static friction between the car's tires and the road is -0.316, what is the range ot speeds for which the car can safely negotiate the turn...
A car is travelling at a flat circular track of radius 25 m and tries to go around at 40 m/sec. a) What should the coefficient of static friction be so the car won’t skid? b) Assume the same car is now travelling at a banked circular track at angle 25o , r=25 m and with same speed. What’s the value of the coefficient of static friction in order for the car not to slide down? c) What would the...
A curve of radius 78 m is banked for a design speed of 100 km/h . Angle θ of the embankment: 45.3 If the coefficient of static friction is 0.39 (wet pavement), at what range of speeds can a car safely make the curve?
7. A highway curve with a radius of R metres is banked so that cars moving at v m/s around the curve do not have to rely on friction when taking the turn. IWPS 7. No.4] 7.1 Show (from first principles) that the angle, 6, at which, the road should be banked is given by: 0 arctan 7.2 A particular banked highway curve with a radius of 200 m is designed for traffic moving at 60 km/h. On a rainy...