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To determine the molarity of the glucose solution, we need to first calculate the moles of glucose present in 1 liter of the solution.
Given:
The solution is 14.5% by mass glucose, which means 100 g of the solution contains 14.5 g of glucose.
The density of the solution is 1.03 g/mL, which means 1 liter of the solution weighs 1030 g.
Using the above information, we can calculate the moles of glucose as follows:
Mass of glucose in 1 liter of the solution = (14.5 g/100 g) x 1030 g = 149.35 g Moles of glucose = Mass of glucose/Molar mass of glucose = 149.35 g/180.16 g/mol = 0.8298 mol
Therefore, the molarity of the glucose solution is:
Molarity = Moles of solute/Volume of solution in liters Molarity = 0.8298 mol/1 L = 0.8298 M
So the molarity of the solution is 0.8298 M.
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