The number of pits in a corroded steel coupon follows a Poisson distribution with a mean...
The number of pits in a corroded steel coupon follows a Poisson distribution with a mean of 5 pits per cm2. Let X represent the number of pits in a 1 cm2 area.
NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part.
Find P(X = 2).
Homework Answers
X ~ poi ( 
)
Where
= 5
Poisson probability distribution is
P(X) = e-
*
X / X!
So,
P(X = 2) = e-5 * 52 / 2!
= 0.0842
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