a coil carries a current of 2 amp which is reduced to zero in 0.8 sec. This cause an induced emf of 0.5 volt. Find the self-inductance
Induced emf in the coil is given by
0.5 = -L*(0-2)/(0.8-0)
L=0.5/2.5
L=0.2 Henry
a coil carries a current of 2 amp which is reduced to zero in 0.8 sec....
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