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it is a pointer operation and how to fix it? #include <stdio.h> int main(){    int...

it is a pointer operation and how to fix it?

#include <stdio.h>

int main(){
   int a[10]={2,5,8,1,4,7,3,10,6,9};
   int *MaxPtr, *MinPtr;
   MaxPtr=&a[0];
   MinPtr=&a[0];
   for (int i=1;i<10;i++){
       if ((*a+i)>*MaxPtr)
       {
           *MaxPtr=*(a+i);
       }
   }
   for (int c=1;c<10;c++){
       if (*(a+c)<*MinPtr)
       {
           *MinPtr=*(a+c);
       }
   }
   printf("Value of the item MaxPtr pointing at: %d\n",*MaxPtr);
   printf("Value of the item MinPtr pointing at: %d\n",*MinPtr);
}

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Homework Answers

Answer #1

/* You are getting wrong result because you are referencing the two pointers to the same array and changing them according to the loops, now when the one pointer is changed correspondingly its values is also copied to the second pointer therefore what you can do either declare second array and copy the content of the first array to it and link second pointer to it or either print the max value before calculating the min value like in the following way */

#include <stdio.h>

int main(){
int a[10]={2,5,8,0,4,7,3,10,6,9};
int *MaxPtr, *MinPtr;
MaxPtr=&a[0];
MinPtr=&a[0];
for (int i=1;i<10;i++){
if (*(a+i)>*MaxPtr)
{
*MaxPtr=*(a+i);
}
}
printf("Value of the item MaxPtr pointing at: %d\n",*MaxPtr);
for (int c=1;c<10;c++){
if (*(a+c)<*MinPtr)
{
*MinPtr=*(a+c);
}
}

printf("Value of the item MinPtr pointing at: %d\n",*MinPtr);
}

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