Question

#include <stdio.h>
#include <stdlib.h>

int aaa();

int main()
{
int ddd,eee = aaa (ddd,eee);
printf("new num 1 = %d, new num2 = %d.\n", ddd,eee);
return 0;
}

int aaa(int bbb,int ccc)
{
   bbb = 111;
   ccc = 222;
   printf("num 1 = %d, num 2 = %d.\n", bbb,ccc);
   return bbb ,ccc;  
}

Output:

num 1 = 111, num 2 = 222.
new num 1 = 0, new num2 = 222.

**************************************************************

I am learning function in C.

When I use the parameter "bbb" and "ccc", can I return the two values at the same time like "return bbb, ccc"?

How can I pass the value of "ddd" and "eee" to "bbb" and "ccc"? and print it out like "new num 1 = 111, new num 2 = 222 "

Thanks

Answer 1

Generally in c programming, a function can return only one value.

For the above scenario, you can use pointers to store the value in the particular address so that we can print the value in the main the changes to the variable in the function are reflected and print the values.

we can use pointers to return multiple values but we are not using any return statement but we use the address of the variables to store the value in the address of the variable

The modified code is as follows:

#include <stdio.h>
#include <stdlib.h>

int aaa();//decalring the function
int main()
{
int ddd,eee;//decalring the varibles ddd and eee
aaa (&ddd,&eee);//calling the unction by passing the values ddd,eee
printf("new num 1 = %d, new num2 = %d.\n", ddd,eee);
return 0;
}

int aaa(int* bbb,int* ccc)
{
*bbb = 111;//storing the value of the bbb in the address of the ddd
*ccc = 222;//storing the value of the ccc in the address of the ccc
printf("num 1 = %d, num 2 = %d.\n", *bbb,*ccc);
//in pointers for printing the values we need to use *variable name

}

The input and output are provided in the screenshot below: