Debug to print output "2 3 5 6 8 11": #include <stdio.h> #include <stdlib.h> int main()...

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Question

Debug to print output "2 3 5 6 8 11": #include <stdio.h> #include <stdlib.h> int main()...

Debug to print output "2 3 5 6 8 11":

#include <stdio.h>
#include <stdlib.h>

int main()
{
int i, j, n;
int A[] = {2, 3, 5, 5, 5, 6, 8, 11, 11, 11};
n = sizeof(A) / sizeof(int);

   for (i = 0; i < n - 1; i++){
       if (A[i] != A[i + 1]) {
           for (j = 1; j < n - 1; j++) {
               A[j] = A[i];
           }
               j++;
           n--;
           i--;
       }
   }
   for (i =0; i < n; i++) {
       printf("%d\n", A[i]);

}
return 0;
}

engineering Computer-Science

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Answer 1

Answer #1

ANSWER: Here I corrected the code and remove the duplicate items from the array and print it Please like it.

CODE:

#include <stdio.h>
#include <stdlib.h>

int main()
{
int i, j,k, n;
int A[] = {2, 3, 5, 5, 5, 6, 8, 11, 11, 11};
n = sizeof(A) / sizeof(int);

for (i = 0; i < n; i++){

for (j = i+1; j < n; j++) {
if(A[i]==A[j])
{
for(k=j;k<n;k++){
A[k]=A[k+1];
}
n--;
j--;
}
}

}

for (i =0; i < n; i++) {
printf("%d ", A[i]);

}
return 0;
}

OUTPUT:

Add a comment

Answer 2

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