49.4-g golf ball is driven from the tee with an initial speed of 50.4 m/s and...
49.4-g golf ball is driven from the tee with an initial speed of 50.4 m/s and rises to a height of 20.5 m. (a) Neglect air resistance and determine the kinetic energy of the ball at its highest point. (b) What is its speed when it is 8.36 m below its highest point?
Homework Answers
a)
max height
H = (v sin x) ^2 / 2g
20.5 = ( 50.4 sin x) ^2 / 19.6
x = 23.436 deg
kE at highest point
kE = 0.5m ( v cos x) ^2
kE = 52.817 J
=====
b)
velocity at the instant given
v' ^2 = (v cos x) ^2 + 2gh
v'^2 = (50.4 cos 23.436)^2 + 2 * 9.8* 8.36
v' = 47.981 m/s
======
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