Question

#include<stdio.h>

#include <stdlib.h>

void read(struct Employee *e);

struct Employee

{

int id;

int age;

};

int main(){

struct Employee e;

read(&e);

}

void read(struct Employee *e){

int a,b;

printf("Enter the id employee\n");

scanf("%d",&a);

printf("Enter the age employee\n");

scanf("%d",&b);

e->id=a;

e->age=b;

}

Question: Declare a pointer variable of type Employee and place the address of the variable created in the above problem in that pointer variable.

Answer 1

So, the answer is like this:

//Declaring a pointer of type Employee

struct Employee *emp_ptr;

//Assigning it the address of variable created in main()

emp_ptr=&e;

Description:

When you define a pointer of type integer, you write it like: int *ptr;

So, to write a pointer of type Employee where Employee is a structure already defined, you can write it like: struct Employee *emp_ptr;

So, emp_ptr is a pointer of type Employee.

In the code given, the Employee variable created is in main() which is 'e'. Its address can be achieved using & operator. So, to assign that address to this newly created pointer, write as...

emp_ptr = &e;

These 2 lines will be written inside main(),

So the modified main() can be written as:

int main(){

struct Employee e;

//Declaring a pointer of type Employee

struct Employee *emp_ptr;

//Assigning it the address of variable created in main()

emp_ptr=&e;

read(emp_ptr);

}

So, see the code above. There's 1 more thing we can change. In the read() function, earlier the address of variable 'e' was passed. Now, that address is stored in emp_ptr pointer so we can directly use that pointer.

So, this is the complete answer for the same. Do comment if there is any query. Thank you. :)