Given the following code find the worst case time complexity
binary search (target: integer, a[1..n ]: ascending integers)
k =1
j =n
loop when (k is less than j)
m =floor((k+j)/2)
if (target is larger than the element at m) then k = m+1
else j = m
endloop
if (target equals element at k) then location=k
else location =0
T(n) = T(n/2) + c = T(n/4) + c + c = T(n/8) + c + c + c ...... ...... ...... = T(n/n) + c + .... + c + c + c [log(n) +1 terms] = c + c + .... + c + c + c [log(n) +1 terms] = clog(n) = Theta(logn)
Given the following code find the worst case time complexity binary search (target: integer, a[1..n ]:...
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