The equation for the combustion of CH4 (the main component of natural gas) is shown below.
How much heat is produced by the complete combustion of 289 g of
CH4?
CH4(g)+2O2(g)→CO2(g)+2H2O(g)ΔH∘rxn=−802.3kJ
Number of moles of CH4 = 289 g / 16.04 g/mol = 18.0 mol
From the balanced equation we can say that
1 mole of CH4 produces 802.3 kJ of heat so
18.0 mole of CH4 will produce
= 18.0 mole of CH4 *(802.3 kJ of heat / 1 mole of CH4)
= 14441 kJ of heat
Therefore, the heat produced by 289 g of CH4 is 14441 kJ
The equation for the combustion of CH4 (the main component of natural gas) is shown below....
What mass of natural gas (CH4) must you burn to emit 258 kJ of heat? CH4(g)+2O2(g)→CO2(g)+2H2O(g)ΔH∘rxn=−802.3kJ
What mass of natural gas (CH4) must you burn to emit 259 kJ of heat? CH4(g)+2O2(g)→CO2(g)+2H2O(g)ΔH∘rxn=−802.3kJ Express the mass in grams to three significant figures.
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