Question

Given the following thermochemical equation for the combustion of methane gas: CH4 (9) + 2O2 (g) → CO2 (g) + 2H20 (1) AH = -8

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Answer #1

given the reaction is

CH4(g) +2O2(g) <===> CO2(g) + 2H2O(l) , ∆H = -890 kJ

from the above reaction 890 kJ energy produce 1 mole of CH4 .

now we convert moles into gram.

i.e.

890 kJ energy produce => 16 g CH4​​​​​​

1 kJ energy produce => 16×1/890 g CH4

132 kJ energy produce => 16×132/890 g CH4

= 2.373 g of CH4

therefore, 2.373 g of methane is required to produce 132kJ of energy.

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