The following thermochemical equation is for the reaction of methane(g) with oxygen(g) to form carbon dioxide(g)...

Question

Question

The following thermochemical equation is for the reaction of methane(g) with oxygen(g) to form carbon dioxide(g) and water(g).

When 6.37 grams of methane(g) react with excess oxygen(g), ___ kJ of energy are _________(evolved or absorbed).

Once you get the answer, would it be a negative number or a positive number?

Answer 1

Answer #1

When 6.37 grams of methane(g) react with excess oxygen(g), ___ kJ of energy are _________(evolved or absorbed).

From the equation

1 mol of CH4 ( 1mol x 16g/mol) reacts energy given out = -802 kJ

If 6.37g of CH4 reacts , the energy released /evolved = 6.37 g of CH4 x -802kJ / 16g of CH4

= - 319.3 kJ

When 6.37g of methane is reacted with excss of O2, 319.3 kJ of energy is evolved.

The sign will be negative number as energy is released (exothermic)

Answer 2

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