Question

K 5 Chapter 18 Acid, Base and Water i Saved 6 attempts left Check my work Be sure to answer all parts. How many moles of H2O* or OH must you add to a liter of strong base solution to adjust its pH from 8.690 to 7.860? Assume a negligible volume change. H2O 1.18 x 10-81 moles of ООН

Answer 1

Initial ph=8.690 Initial pon = (14-8.690) =5.31 final pH = 7.860 final pon = (14 7.866) = 6.14 = Concentration of onion We know, pHT POW=14 ond pow -- 109 [ON] cobear Tow So, Initial Com] =10-5. =4.898*10-6 (M) and final [or] = 10-6.14 = 7.24 810-7 (M)

So, difference in cow] = [ow)wiktion - Cow Joinen (4-898 910-) - (7.24.710-7) – 4.174810-6(M) Now, Imol of Wton hot would neutralise 1 mol of ON Now, as the vol of the solo i 1lt so, number of mores of difference of On- would be 4.174 x 10-6. So, 40174810-6 moles of Noot would be seguind to adjust the PN from 8.690 60 7.860
If you still have any query feel free to ask in the comments and if you like my work please give a thumbs up.