Suppose you are testing the hypotheses H0: μd = 0 and Ha: μd ≠ 0 in a paired-design and obtain a p-value of 0.21. Which one of the following could be a possible 95% confidence interval for μd?
A) 4.50 to 6.90
B) 1.50 to 3.80
C) -1.20 to .90
D) -2.30 to -.70
C) -1.20 to .90
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Suppose you are testing the hypotheses H0: μd = 0 and Ha: μd ≠ 0 in...
Suppose that you are testing the hypotheses H0: μ=70 vs. HA: μ≠70. A sample of size 41 results in a sample mean of 65 and a sample standard deviation of 1.7. a) What is the standard error of the mean? b) What is the critical value of t* for a 99% confidence interval? c) Construct a 99% confidence interval for μ. d) Based on the confidence interval, at α=0.010 can you reject H0? Explain.
need help: Suppose that you are testing the hypotheses H0 με 16 vs. HA: μ< 16. A sample of size 16 results in a sample mean of 15.5 and a sample standard deviation of 20 a) What is the standard error of the mean? b) What is the critical value of t* for a 90% confidence interval? c) Construct a 90% confidence interval for μ. d) Based on the confidence interval, at α#0.05 can you reject Ho? Explain. a) The...
Consider the following competing hypotheses: Use Table 2. H0: μD ≥ 0; HA: μD < 0 d-bar = −4.3, sD = 7.2, n = 15 The following results are obtained using matched samples from two normally distributed populations: a. At the 1% significance level, find the critical value(s). (Negative value should be indicated by a minus sign. Round intermediate calculations to 4 decimal places and final answer to 2 decimal places.) Critical value b. Calculate...
The null and alternate hypotheses are: H0 : μd ≤ 0 H1 : μd > 0 The following sample information shows the number of defective units produced on the day shift and the afternoon shift for a sample of four days last month. Day 1 2 3 4 Day shift 11 12 14 18 Afternoon shift 9 10 13 16 At the .005 significance level, can we conclude there are more defects produced on the afternoon shift? Hint: For the...
The null and alternate hypotheses are: H0 : μd ≤ 0 H1 : μd > 0 The following sample information shows the number of defective units produced on the day shift and the afternoon shift for a sample of four days last month. Day 1 2 3 4 Day shift 11 10 14 19 Afternoon shift 10 9 14 16 At the .01 significance level, can we conclude there are more...
The null and alternate hypotheses are: H0 : μd ≤ 0 H1 : μd > 0 The following sample information shows the number of defective units produced on the day shift and the afternoon shift for a sample of four days last month. Day 1 2 3 4 Day shift 10 12 15 19 Afternoon shift 8 11 12 20 At the 0.050 significance level, can we conclude there are more defects produced on the day shift? Hint: For the...
Suppose a test of H0: μ = 0 vs. Ha: μ ≠ 0 is run with α = 0.05 and the P-value of the test is 0.052. Using the same data, a confidence interval for μ is also constructed. (a) Of the following, which is the largest confidence level for which the confidence interval will not contain 0? 90% 94% 95% 96% 99% (b) Of the following, which is the smallest confidence level for which the confidence interval will contain...
The null and alternate hypotheses are: H0 : μd ≤ 0 H1 : μd > 0 The following sample information shows the number of defective units produced on the day shift and the afternoon shift for a sample of four days last month. Day 1 2 3 4 Day shift 12 12 16 19 Afternoon shift 10 10 12 15 At the .05 significance level, can we conclude there are more...
We wish to test H0: = 0 versus Ha: > 0. If we calculate a test statistic of = 0.6, then my p-value will be closest to 0.003 0.300 0.600 0.950 When estimating , the proportion of voting age citizens who will vote for Candidate A, political researchers calculate the 90% confidence interval (0.67, 0.73). If we were to also test the hypotheses H0: = 0.666 versus Ha: 0.666 using a significance level of = 0.10, we would decide to accept H0. reject H0. not reject...
We are interested in testing the following hypotheses. H0: P1- P2 ³ 0, Ha: P1- P2 < 0. The test statistic Z is computed to be 0.58. The p-value for this test is A. 0.2810 B. 0.7190 C. 0.5620 D. 0.5800